PROBLEM 03 – 0328: A ball of mass 0.2 kg is thrown vertically upwards by applying a force by hand. if the hand moves 0.2m while applying the force and the ball goes up to 2m height further find the magnitude of the force. (Consider g = 10 ms–1)
(A) 16 N (B) 20 N
(C) 22 N (D) 4 N
Answers
Answered by
0
F=mgh
=0.2×10×2
=4N
so the answer is 4N
=0.2×10×2
=4N
so the answer is 4N
adityarindhe50:
hey man but given answer is 22 by my teacher
Answered by
1
Heya❤❤
Ur answer is: option (c) 22N //this is enough for 1 Mark or for mcq
Explanation::
The work/energy input to the system is
W=E=(F−mg)δ
This energy is completely transformed into potential energy so
(F−mg)δ=mgh
with
F=mg(1+hδ)
here
δ=0.2 [m]
m=0.2 [K]
h=2 [m]
then
F=0.2⋅10(1+20.2)=22 [N]
hope it helps
✌✌✌
Ur answer is: option (c) 22N //this is enough for 1 Mark or for mcq
Explanation::
The work/energy input to the system is
W=E=(F−mg)δ
This energy is completely transformed into potential energy so
(F−mg)δ=mgh
with
F=mg(1+hδ)
here
δ=0.2 [m]
m=0.2 [K]
h=2 [m]
then
F=0.2⋅10(1+20.2)=22 [N]
hope it helps
✌✌✌
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