Question

Problem

1 A stream of charged particle is moving with a velocity of 500 m/s in a region of crossed fields. If the magnitude of electric field is 1000 V/m, find the magnitude of magnetic field?​

Answer 1

Given v=2*10^ 3 m/s

B = <1.5T

As the particle passes undeflected, thus electric force is balanced by the magnetic force acting on the particle. .. qE=q(v x B)

E = Bv = 1.5 × 2 × 10³ = 3 × 10³

NC-1