Question

Problem 1 : The three identical samples of
potassium chlorate are decomposed. The mass
of oxygen is determined to be 3.87 g, 3.95 g and
3.89 g for the set. Calculate absolute deviation
and relative deviation.

:today i study analytical chemistry, confuse to solve questions.​

Answer 1

Absolute deviation=0.03

Realtive deviation=0.76

Explanation:

Mean=3.87+3.95+3.89/3

=9.271/3

=3.90

Absolute deviation=|observed value-mean|

1 .|3.87-3.90|=0.03

2.|3.95-3.90|=0.05

3.|3.89-3.90|=0.01

Mean of absolute deviation=0.03+0.05+.0.01/3

=0.09/3

=0.03

Realtive deviation=0.03/3.90×100%

=0.76

Answer 2

Answer:

The three identical samples of potassium chlorate are decomposed. The mass

of oxygen is determined to be 3.87 gram 3.95 Gram and 3.89 grams for the set.

Calculate the absolute deviation and relative deviation