Question

Problem #1: What is the percent by volume of a solution formed by mixing 25mL of isopropanol with 45mL water? Problem

#2: A photographic “stop bath” contains 160mL of pure acetic acid, HC2H3O2(l) in 650mL solution. What is the v/v concentration of acetic acid in the stop bath?​

Answer 1

Answer:

Answer for Problem #1

35.7%

Explanation:

Volume of isopropanol = 25ml

Volume of Water = 45ml

Volume of Solution = 25ml + 45ml = 70ml

Percent of solution = 25ml/70ml x 100

= 35.71 %