Problem - 13.6: A gas expands from 10 litre to 20
litre at a constant pressure of 2 atmospheres. What is
the work done by the gas during the expansion?
(1 atmosphere = 1.013 x 10 Pa)
Answers
Answered by
0
Answer:
u
Explanation:sucks
Answered by
0
Answer:
W= (-20* 101.3) J
Explanation:
V1= 10L
V2= 20L
P= 2atm
W= -P ∆V
= -2 (20-10)
= -20Latm
= (-20*101.3)J
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