Question

Problem #2: A photographic "stop bath" contains 160mL of pure acetic acid,
HC2H302m in 650ml solution. What is the v/v concentration of acetic acid
in the stop bath?​

Answer 1

Answer:

$v \div v \: concentration \: = \frac{solute \: volume}{volume \: of \: the \: solution} \times 100 \\ \\ \frac{160}{160 + 650} \times 100 = \frac{1600}{65} = 24.6\%$

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Answer 2

The v/v concentration is 24.6%.

Given - Volume of solute and solvent

Find - v/v concentration

Solution - The v/v concentration can be calculated as -

Concentration = volume of solute/volume of solution*100

Concentration = $\frac{160}{650} \times 100$

Concentration = 24.6%

Hence, the v/v concentration is 24.6%.

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