Question

Problem # 2 An impulse of 20 kg·m/s acts on the particle in problem # 1, in the same direction as the velocity. What is the final velocity of the particle?

Answer 1

Answer:

Explanation:

m = 10 kg

take, t = 1 sec

u = 5 m/s

momentum = m×v

=10 × 5

= 50 kg m/s

Impulse = force × t

= ma × t

20 = 10 a × 1

a = 2 m/s^2

v = u + at

= 5 + 2 × 1 = 7 m/s