Problem 2. Whats going on here?! 1 p d 1 d p .1/.1/ d p 1 p 1 d p 2 1 d 1: (a) precisely identify and explain the mistake(s) in this bogus proof. (b) prove (correctly) that if 1 d 1, then 2 d 1. (c) every positive real number, r, has two square roots, one positive and the other negative. The standard convention is that the expression p r refers to the positive square root of r. Assuming familiar properties of multiplication of real numbers, prove that for positive real numbers r and s, p rs d p r
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