Question

Problem 25. A hydrogen atom moving at a speed of v
absorbs a photon of wavelength 122 nm and stops. Find the
value of v. Mass of hydrogen atom=1.67x10-2 kg.​

Answer 1

Hydrogen atom moving at a speed of 3.25 m/s

Explanation:

Given,

wavelength , $\lambda$ = 122 nm = $122\times 10^{-9}$

mass of hydrogen, m = $1.67\times 10^{-27}$ kg

we know that ,

$m \times v - p = m(0) = 0$

∵ $p = \frac{h}{\lambda}$

∴ $m\times v = \frac{h}{\lambda}$

or,

v = $\frac{h}{m\times \lambda}$

v = $\frac{6.62\times 10^{-34}}{1.67\times 10^{-27}\times 122\times 10^{-9}}$

v = 3.25 m/s

Hydrogen atom moving at a speed of 3.25 m/s

Answer 2

Answer:

hola mate

a speed of 3.25 m/s

Explanation:

Given,

wavelength , $\lambdaλ = 122 nm = 122\times 10^{-9}122×10$

−9

mass of hydrogen, m = $1.67\times 10^{-27}1.67×10$

−27

kg

we know that ,

m \times v - p = m(0) = 0m×v−p=m(0)=0

∵ p = $\frac{h}{\lambda}$p=

λ

h

∴ m\times v = $\frac{h}{\lambda}m×v= </p><p>λ$

h

or,

v =$\frac{h}{m\times \lambda}$

m×λ

h

v = $\frac{6.62\times 10^{-34}}{1.67\times 10^{-27}\times 122\times 10^{-9}}$

1.67×10

−27

×122×10

−9

6.62×10

−34

v = 3.25 m/s

Hydrogen atom moving at a speed of 3.25 m/s

hope it's helpful for you