Problem 3: At what height from the centre of
the Earth the acceleration due to gravity will be
1/4 of its value as at the Earth.
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Answer:
radius of earth = 6,371 km
Explanation:
We have the formula, g' = g/(1+h/R)^2
Here ,
g' = acceleration due to gravity at the height
g = 9.8m/s^2
R = radius of earth
h = height
g/g' = (1+h/R)^2
4 = (1+h/R )^2
1+h/R = 2
h/R = 1
h = R
So at the height of 6371 km the value of g is 1/4 th of its original value.
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