Problem: (34) Calculate volume of water to be added 100 ml of 0.4 M solution of NaOH to
convert it into 0.1 M solution.
Problem: (35) what is molarity of solution prepared by diluting 250 ml of 0.4 m sulphuric acid
with 1000 ml of water.
Pls help me out
Answers
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Answer:
1) Molarity=
V(solution)
n
M
1
=
V
1
(solution)
n
...(1)
M
2
=
V
2
(solution)
n
...(2)
From (1) and (2)
M
2
M
1
=
V
1
V
2
substituting the values,
V
2
=
0.5M
2M×100ml
V
2
=400ml
Hence, V
2
−V
1
=400ml−100ml=300ml
Therefore, 300ml of water is added to the solution.
2) Normality = Molarity × Valency factor of H
2
SO
4
=0.5×2 N
Normality =1N
Now,
N
1
V
1
=N
2
V
2
⇒1×1 L=N
2
×10 L
⇒N
2
=0.1N
Explanation:
I hope this will helps u
thanks for reading
I am in 8th now
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