Question

Problem: (35) What is molarity of solution prepared by diluting 250 ml of 0,4 M sulphuric acid
with 1000 ml of water.​

Answer 1

Answer:

Molarity, M=

volume(L)

no. of moles

Volume, V=250mL=0.25L

No. of moles, n= mass/molar mass

Mass = 49 g

Molar mass of H

2

SO

4

= 98 g

n=49/98=0.5

M=0.5/0.250=2M