Problem: (35) What is molarity of solution prepared by diluting 250 ml of 0,4 M sulphuric acid
with 1000 ml of water.
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Answer:
Molarity, M=
volume(L)
no. of moles
Volume, V=250mL=0.25L
No. of moles, n= mass/molar mass
Mass = 49 g
Molar mass of H
2
SO
4
= 98 g
n=49/98=0.5
M=0.5/0.250=2M
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