Question

Problem 7.21
The pH of 0.004M hydrazine solution is
9.7. Calculate its ionization constant K
and pkb...


hey guys.....hru all

Solve the question fast...​

Answer 1

NH2NH2 + H2O -----> NH2NH3+ + OH-

From   the  given pH   the Hion concentration can be measured.

So, we have

[H+] = antilog (–pH) = antilog (–9.7) = 1.67 × 10^-10

Now, [OH-]  = Kw / [H+] = 1 × 10^-14/ 1.67 × 10^-10                         = 5.98 × 10^-5//

The concentration of the corresponding hydrazine ion is also the same as that of hydroxyl ion. The concentration of both these ions is very small so the concentration of the undissociated base can be taken equal to 0.004 M

Thus, Kb= [NH2NH3+][OH-] / [NH2NH2]= (5.98 × 10^-5)^2/ 0.004 = 8.96 × 10^-7//

So, pKb = –logKb = –log(8.96 × 10–7) = 6.04//

Hope this helps u✌✌

Answer 2

Answer:

sorry for answering her,the answer for recoil question you asked is as follows

Explanation:

when a bullet is fired it get a backward gerk,due to the motion of bullet forward it is according to newton's third law.

Both bullet and gun get same velocity but due to the difference in sizes bullet easily travels fastly due to it's small size.

option c is correct "" lesser ""