Question

Problem 93. A particle is moving along a circular path of radius 2 m and with uniform speed of 5 ms. What will be the
change m velocity when the particle completes half of the revolution
(a) Zero
(b) 10 ms
(c) 1025
(d) 10/2ms​

Answer 1

Explanation:

$area \: of \: circle \: = \pi \: r$

3.14×2= 6.28m

Half of revolution = 6.28÷2= 3.14

Speed of particle = 3.14× 5= 15.7ms