Question

Problem: A particle of mass 1.67 x 10-27 kg and charge 1.6 x 10-19c, is to be held motionless b/w two horizontal plates, the voltage applied b/w the plates is 14.32 x 10-'volt. Calculate the distance b/w the plates? ​

Answer 1

Answer:

proton is held motionless between two horizontal metal plates 10 cm apart. What voltage should be applied between the plates?

Solution: = 1.67 ∙ 10−27 kg, mass of proton = 1.6 ∙ 10−19 C, charge of proton = 0.1 m The gravitational force on a proton would be balanced by the electric field. Balance of forces

: = v Therefore, v = = 1.67 ∙ 10−27 ∙ 9.8 ∙ 0.1 1.6 ∙ 10−19 ≈ 1 ∙ 10−8 Output: 1 ∙ 10−8

Explanation:

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