Question

Problem: How much work is done in
moving a Charge of 3c from a point at 110v to 125v​

Answer 1

Given ,

• A charge of 3 c from a point at 110 v to 125 v

We know that ,

The work done to move a unit charge from one point to another point is called potential difference

Mathematically ,

$\boxed{ \tt v_{b} - v_{a} = \frac{ w_{ab}}{q} }$

Thus ,

$\tt \implies 125 - 110 = \frac{w}{3}$

$\tt \implies w = 15 \times 3$

$\tt \implies w = 45 \: \: joule$

Hence , the work done is 45 J

Answer 2

Answer:

45joule

Explanation:

here $V_{A}$=110volt; $V_{B}$=125volt

and also $q_0$=3c

since work $W_{AB}$ is given by

$V_{B}$-$V_{A}$=$\frac{W_{AB}}{q_{0}}$

125-110=$\frac{W_{AB}}{3}$

15*3=$W_{AB}$

$W_{AB}$=45joule

$<p style="color:cyan;font-family:cursive;background:black;font size:25px;"> your answer is 45 joule$