Question

Problem no 11
Plz zzzzzzz

Answer 1

Answer:

If x³ + bx² + cx + d, is divisible by (x + 3), (x + 4), & (x + 5)

-3, -4 , and -5 must be it's zeroes.

But as it is a cubic polynomial, it can have at most three zeroes. So, -3, -4, and -5 are all the zeroes of the polynomial.

. => x³ + bx² + cx + d = (x + 3)(x + 4)(x + 5)

= (x² + 4x + 3x + 12)(x + 5)

= (x² + 7x + 12)(x + 5)

= x³ + 5x² + 7x² + 35x + 12x + 60

= x³ + 12x² + 47x + 60

Therefore, answer is option (b)