Problem solving
Direction : solve what is asked
1. How much force is needed to transfer a 30 kg balikbayan box to a height of 10 meters
2. Determine the force applied on a 20 kg object that moves at a rate of 0.5 m/s².
3. A bullet is fired and hits on a 25 kg block of wood and moves into 2.0m/s².How much force is applied to the wood.
4. A student drops a 2.0g ice water on the floor since building. How much force will be exerted on the ice water upon impact on the ground?
5. A 300 kg boat floats on the water. How much upward force will the water apply to the boat?
Answers
a science search them
please like this answer
1.
- Force needed to transfer a 30 kg balikbayan box to a height of 10 m can be calculated by the formula
F = ma
- Here, mass of box = 30 kg
acceleration = acceleration due to gravity = 10 m/s²
So, F = 30 kg × 10 m/s² = 300N
300 N is needed to transfer a 30 kg balikbayan box to a height of 10 meters.
2. To make an object of mass =20 kg
move with an acceleration = 0.5 m/s² force required is
F = 20 × 0.5 = 10 N
Therefore, 10 N needs to be applied to move a 20 kg object at the rate of 0.5 m/s².
3. Mass of wood = 25 kg
Acceleration of bullet in wood = 2 m/s²
- Force applied on the wood is given by
F = ma
⇒ F = 25 kg × 2 m/s²
⇒ F = 50 N
Therefore, 50 N force is applied to the wood.
4. Mass of ice block = 2 g = 0.002 kg
- When ice drops on the ground, it will experience acceleration due to gravity, so force exerted is given by
F = 2 × × 10 = 0.02 N
Therefore, the block of ice experiences a force of 0.02 N upon impact on the ground.
5. Mass of boat = 300 kg
If boat is floating, it is experiencing buoyant force equal to its own weight.
F = mg
⇒ F = 300 kg × 10 m/s²
⇒F = 3000 N
Therefore, a force of 3000 N is applied by water on the boat.