Science, asked by zyrilmaerobiato, 1 month ago

Problem solving
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1. How much force is needed to transfer a 30 kg balikbayan box to a height of 10 meters

2. Determine the force applied on a 20 kg object that moves at a rate of 0.5 m/s².

3. A bullet is fired and hits on a 25 kg block of wood and moves into 2.0m/s².How much force is applied to the wood.

4. A student drops a 2.0g ice water on the floor since building. How much force will be exerted on the ice water upon impact on the ground?

5. A 300 kg boat floats on the water. How much upward force will the water apply to the boat?

Answers

Answered by deyprity619
0

a science search them

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Answered by AnkitaSahni
0

1.

  • Force needed to transfer a 30 kg balikbayan box to a height of 10 m can be calculated by the formula

                                                F = ma

  • Here, mass of box = 30 kg

         acceleration = acceleration due to gravity = 10 m/s²

          So,                    F = 30 kg × 10 m/s² = 300N

300 N is needed to transfer a 30 kg balikbayan box to a height of 10 meters.

2. To make an object of mass =20 kg

move with an acceleration = 0.5 m/s² force required is

                           F = 20 × 0.5 = 10 N

Therefore, 10 N needs to be applied to move a 20 kg object at the rate of 0.5 m/s².

3. Mass of wood = 25 kg

   Acceleration of bullet in wood = 2 m/s²

  • Force applied on the wood is given by

                                       F = ma

                                  ⇒    F = 25 kg × 2 m/s²

                                  ⇒   F = 50 N

Therefore, 50 N force  is applied to the wood.

4.      Mass of ice block = 2 g = 0.002 kg

  • When ice drops on the ground, it will experience acceleration due to gravity, so force exerted is given by

                          F = 2 × 10^{-3} × 10 = 0.02 N

Therefore, the block of ice experiences a force of 0.02 N upon impact on the ground.

5. Mass of boat = 300 kg

If boat is floating, it is experiencing buoyant force equal to its own weight.

                             F = mg

                         ⇒ F = 300 kg × 10 m/s²

                         ⇒F = 3000 N

Therefore, a force of 3000 N is applied by water on the boat.

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