Math, asked by kp145308, 1 year ago


Problem
The sum of 333 consecutive odd numbers is 515151.
What is the second number in this sequence?

Answers

Answered by mysticd
1

Answer:

 \green {Second \: term \: in \: sequence = x+2 = 1215+2 = 1217}

Step-by-step explanation:

Let x, (x+2),(x+4), ...,333 terms are consecutive odd numbers are in A.P

First term (a) = x ,

Common difference (d) = 2,

Number of terms = n

 \boxed { \pink {Sum \: of \: n\:terms \:(S_{n})=\frac{n}{2}[2a+(n-1)d]}}

 S_{333} = 515151\:(given)

\implies \frac{333}{2}[2x+(333-1)2]=515151

\implies \frac{333}{2}\times 2(x+332)=515151

\implies 333(x+332)= 515151

\implies x+332 = \frac{515151}{333}

\implies x + 332 = 1547

\implies x = 1547 - 332

 \implies \blue {x = 1215}

 Now\\ ,\green {Second \: term \: in \: sequence = x+2 = 1215+2 = 1217}

Therefore.,

 \green {Second \: term \: in \: sequence = x+2 = 1215+2 = 1217}

•••♪

Answered by STRAIGHTFOREVER
0

Answer:

17

Source:

Just trust me bro

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