Question

Problem: What Number Am I?

I am a five-digit number made of the digits 0. 3, 4, 6, and 9. In my number, the following are true.

• The digit 4 is in a position whose place value is 10 times the place value of the position of the digit 9 and 100 times the place value of the position of the digit 0.
• The digit 3 is in a position whose place value is 100 times the place value of the position of the digit 9
• The digit 0 is in a position whose place value is 10 times the place value of the position of the digit 6
What number am I?​

Answer 1

Answer:

93404. this is the answer

Answer 2

Given: Digits 0, 3, 4, 6 and 9

To find: The 5 digit number formed by these based on given conditions

Solution: According to the given problem,

1) 4 is in a position whose place value is 10 times the place value of 9 and 100 times the place value of 0.

Now, we know that place values in number system are written in the form of increasing power of 10 starting from unit place i.e., unit, tens, hundreds...

Place value of a digit at tens place is 10 times the place value of digit at unit place and place value of digit at hundreds place is 10 times the value of digit at tens place and 100 times the digit at unit place.

So, based on the given condition, 4, 9 and 0 are together following the same order i.e., 490

2) Place value of digit 3 is 100 times the place value of 9.

It means 3 exists at the left of 4 as 3490

3) Place value of 0 is 10 times the place value of 6.

It means 6 is on the right side of 0 i.e., at unit place as 34906.

Hence, the required five-digit number is 34906.