Probleme combinate
254
Diferenta
doilea număr este cu 72 mai mare decat
a doua numere este 140. Af
dublul primului număn Care sunt
Answers
Given:
Vertices of Parallelogram – A(-2,-1), B(4,-1), C(0,2) and D(6,2).
The smaller coungruent sides of Parallelogram is having length of 3.6 units.
To Find:
Area of Parallelogram & Perimeter of Parallelogram.
Solution:
Diagonals of Parallelogram divides it into two congruent triangles, which are ∆ ABC and ∆ ACD.
Therefore,
Area of Parallelogram = Area of ∆ ABC + Area of ∆ ACD.
Formula for calculating Area of Triangle
→ Area of ∆ ABC
→ Area of ∆ ACD
Area of Parallelogram = Area of ∆ ABC + Area of ∆ ACD.
Area of Parallelogram = 9 units + 9 units
______________________
Perimeter of Parallelogram = 2(a + b)
where a = side and b = base of Parallelogram.
a = AD = 3.6 units (given), b = AB = ?
We can find base by using distance formula:
Perimeter of Parallelogram = 2(a + b)
= 2(3.6 + 6) units
= 2(9.6) units
Hence, the area of Parallelogram is 18 units and Perimeter of Parallelogram is 19.2 units.