Problems:
1. A man standing on top of a cliff observes the angles of depression of the top and bottom of a tower 100 metres away from the foot of the cliff as 45 degrees and 60 degrees
respectively. Find the length of the tower.
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Answer:
tan60=
x
100
3
=
x
100
x=
3
100
Similarly ,
tan30=
y
100
3
1
=
y
100
y=100
3
Therefore,
x+y=
3
100
+100
3
x+y=
3
400
m
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