Question

PROBLEMS FOR PRACTICE
1. A current of 4 amp when passed through AgNO3 solution for 25 minutes deposite 6.66 g
of Ag. Calculate electrochemical equivalent of silver
Ans. 0.0011 glamp/sec.)
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Answer 1

Answer:

According to the data given when 11 e is passed the amount of silver,

deposited is 0.0011180\,g0.0011180g

\therefore (0.5\times 200)c∴(0.5×200)c is passed

then (0.0011180\times 100)g(0.0011180×100)g

of silver gets deposited

=0.11180\,g=0.11180g