Math, asked by yogithakotian76, 4 months ago

Problems on simple Quadrlaterals​

Answers

Answered by sunakat483
0

Answer:

Given: m∠A = 3x+9 m∠B = 5x+20

m∠C = 3x m∠D = 2x+6

Find m∠D.

Solution: 3x+9 + 5x+20 + 3x + 2x+6 = 360

13x + 35 = 360; 13x = 325; x = 25

m∠D = 2(25)+6 = 56º

Remember:

• All four sided figures (regardless of their shapes) have angles whose measures add to 360º.

• Read carefully for what is needed as an answer. This question asks for the angle measure, not for just the value of x.

Answered by nigarg82
1

Answer:

Formulae regarding polygons:-

1. Angle sum property

(n - 2)180 where ‘n’ is the number of sides

2. Number of sides when sum of exterior angle Is given:-

\frac{360}{n}  where ‘n’ is the number of sides

3. Sum of interior angle:-

\frac{(n - 2)180}{n}  where ‘n’ is the number of sides

Remember facts:-

1. In a regular polygon, all the sides and angles are of equal measure.

2. The sum of all exterior angles is always 360 degrees.

Hope it helps

Please mark my answer as BRAINLIEST

Similar questions