Question

PROBLEMS:
P5.1 A bullet of mass 0.04 kg moving with a speed of 90 ms' enters a heavy wooden block and is
topped after a distance of 60 cm. What is the average resistive force exerted by the block on the
bullet? (Ans: 270 N)​

Answer 1

Answer:

solution

Explanation:

Solution :

Here , m=0.04kg,u=90ms−1

υ=0,s=6=cm=0.6m,F=?

From υ2−u2=2 as

0−902=2a×0.6

a=−9×902×0.6=−6750ms−2

From F=ma=0.04×(−6750)=−270N

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