Question

Proceed the above question in an easy way.....

Answer 1

Answer:

Proved

Step-by-step explanation:

From triangle PSN and triangle MRQ

PS = QR (Because PQRS is a parallelogram and opposite sides are equal in a parallelogram)

SN = ½ SR (N is midpoint of SR)

MQ = ½ PQ (M is midpoint of PQ)  

But SR = PQ

½ SR = ½ PQ

So SN = MQ

Now PSN = MQR (opposite angles are equal)

Triangle PSN is congruent to triangle MQR (From SAS postulate)

Therefore PN = MR

Now PM = ½ PQ

        NR = ½ SR

Thus PM = NR

We also know PQ is parallel to SR

Therefore ½ PQ is parallel to ½ SR

   Hence PM is parallel to NR

So PNRM is a parallelogram

MR and PN trisects the diagonal PQ (By midpoint theorem)

Thus QA = AB = BS