Math, asked by bushra010303, 1 year ago

process of this sum?

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Answered by anushkachopada
0

 =  \frac{ \ \sec ^{2} \alpha  -   { \tan^{2} \alpha } }{2( { \cos^{2} 48 } +  \sin^{2} 48)  }  +  \frac{2 \tan^{2} 30  \frac{1}{ \cos^{2} 52 }  \sin^{2} 38 } { \sec^{2} 20 -  \tan^{2} 20  }  \\  =  \frac{1}{2(1)}  + 2( \frac{ \frac{1}{ \sqrt{3} } }{1}) \\  =  \frac{ \sqrt{3}  + 4}{2 \sqrt{3} }
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