Question

producing an acceleration of 400m/s2 body of 10g which require more force ​

Answer 1

Given:-

• Acceleration ,a = 400m/s²

• Mass ,m = 10g = 10/1000 = 0.01 kg

To Find:-

• Force required ,F

Solution:-

As we know that force is defined as the product of mass and acceleration.

• F = ma

where,

F is the force

m is the mass

a is the acceleration

Substitute the value we get

→ F = 400×0.01

→ F = 4×1

→ F = 4 N

Therefore, the force required is 4 Newton.

Some Additional Information !!

• The rate of change of velocity at per unit time is called acceleration .

• SI unit of acceleration is m/s²

• It is vector Quantity ( both magnitude and direction).

Answer 2

$\bigstar \: \tt \sf \: solution \\ \bigstar \: f = ma \\ \bigstar \tt m = mas. \\ \bigstar \tt \: a = acceleration. \\ \bigstar \tt \: f =force. \\ \rightarrow \tt \: f = 400 \times 0.01 \\ \rightarrow \tt \: f = 4 \times 1 \\ \rightarrow \tt \: f = 4 \\ \bigstar \: 4 \tt \: answer \\ \\ \\ \tt \bold{good \: to \: know :: } \\ 1.\sf to \: rate \: of \: change \: of \: velocity \: of \: \\ \sf \: per \: unit \: time \: is \: called \: acceleration. \\ 2. \sf \: si \: unit \: of \: accereration \: is \: \frac{m}{s} ^{2} \\ 3. \sf \: it \: is \: vector \: quantity \: \: both \: magnitude \: and \: dirction.$