Question

product 620*28a is divisible by 15

Answer 1

Answer:

Mark as brainliest answer.

Step-by-step explanation:

→ To show= That product of 620*28a is divisible by 15.

→ we have to find value of a .

→ Let value of a = 15

→ 620*(28×15)/15

→ 620*420/15

→ 260400/15

→ 17360

→ It is there, the number is fully divided with remainder is 0.

→ Now we have so many value of a . as we can take multiple of a.

→ a = 15

→ now its multiple means,

→ 15 × 2 = 30 [this can be also put up in value of a][remainder will be 0.]

→ 15 × 3 = 45 [this can be also put in value of a][remainder will be 0.]

→ so it is true that product 620*28a is divisible by 15.

→ And the value we get after dividing it is 17360.

Answer 2

CORRECT QUESTION

If the product 620*28a is divisible by 15. Find the value of a.

ANSWER

The value of a can be 2, 5, or 8.

GIVEN

620*28a

TO FIND

The value of a.

SOLUTION

We can simply solve the above problem as follows;

A number is divisible by 15 if it is divisible by both 3 and 5.

We know that,

A number is divisible by 3 if the sum of the digits is divisible by 3.

And,

A number is divisible by 5 if the units place is either 5 or 0.

Given

620 × 28a

620 is divisible by 5 since the units digit is zero.

So, 620 × 28a is divisible by 5.

Now, 28a must be divisible by 3.

Therefore,

The sum of the number 28a should be divisible by 3.

2 + 8 + a = 10+a is divisible by 3

Hence, The value of a can be 2, 5, or 8.

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