Question

product ab.
(CBSE 2019)
The LCM of two numbers is 9 times their HCF. The sum of LCM and HCF
is 500. Find their HCF.
[CBSE 2019C​

Answer 1

Step-by-step explanation:

9x+x = 500

10x=500

x =50

therefore HCF =50

Answer 2

Answer:

$\huge \red a \red n \red s \red w \red e \red r \over$

Given:-

LCM:- 9×HCF

LCM+HCF = 500

To Find:-

The value of LCM

$\huge \green s \red o \orange l \green u \red t \green i o \red n \over$

LCM+HCF = 500

Given LCM = 9HCF

9HCF + HCF= 500

10 HCF = 500

$\: hcf = \frac{500}{10} = 50$

HCF = 500

• Using HCF= 50 in LCM + HCF = 500

• LCM+ HCF= 500 [HCF = 50]

• LCM + 50 = 500

• LCM = 500 - 50

• LCM = 450

$\huge hence \: verified$