Product is 600 and sum is 10 what will be the number
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Answer:
5+5√23i
5+5√23i5-5√23i are the imaginary numbers which satisfy given conditions
Step-by-step explanation:
xy=600
x+y=10..............(1)
(x-y)^2=(x+y)^2-4xy
=10^2-4(600)
=100-2400
=-2300
x-y. =√(-23×100)
=√(-1×23)√100
=√23i*10
=10√23i..........(2)
by solving (1)&(2)
2x=10+10√23i
x=5+5√23i
substitute in equation(1)
y=10-5-5√23i
=5-5√23i
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