Question

product of 1st and 2nd number is 16.2 2nd and 3rd is 19.08 1st and 3rd is 23.85. Find the numbers​

Answer 1

Let the first no. be x

the second no. be y

the third no. be z

according to the condition,

$xy = 16.2 \\ yz = 19.08 \\ zx = 23.85 \\ \\ {x}^{2} {y}^{2} {z}^{2} = 16.2 \times 19.08 \times 23.85 \\ xyz = 85.86 \\ \\ z = \frac{85.86}{16.20} \\ z = 5.3 \\ \\ x = \frac{85.86}{19.08} \\ x = 4.5 \\ \\ y = \frac{85.86}{23.85} \\ y = 3.6$

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