Question

product of 2 numbers is 65whole 1/3.if one of them is 12 whole 1/4. Find the other​

Answer 1

Answer:

16/3

Step-by-step explanation:

12 1/4 = 49/4 ( converting to improper)

65 1/3 = 196/3

let the unknown value be x

49/4 * x = 196/3

49x = 196/3 * 4

49x = 784/3

x = 784/3 / 49

x = 784/3 * 1/49

x = 16/3

therefore, the required value is 16/3

hope it helps you

Answer 2

Answer :-

• The other number is 16/3.

To find :-

• The other number.

Step-by-step explanation :-

• Here, it is given that the product of 2 numbers is 65 1/3 and one of the numbers is 12 1/4. We have to find the other number!

Let :-

• The other number be "x".

Then :-

• The product of 12 1/4 and "x" will be 65 1/3.

Therefore,

$\dashrightarrow\sf12 \dfrac{1}{4} \times x = 65 \dfrac{1}{3}$

$\dashrightarrow\sf\dfrac{49}{4} \times x = \dfrac{196}{3}$

$\dashrightarrow \sf x = \dfrac{196}{3} \div \dfrac{49}{4}$

$\dashrightarrow\sf x = \dfrac{196}{3} \times \dfrac{4}{49}$

Cancelling the numbers,

$\dashrightarrow\sf x = \dfrac{4}{3} \times \dfrac{4}{1}$

$\dashrightarrow\sf x = \dfrac{16}{3}$

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V E R I F I C A T I O N

• To check our answer, let's find the product of 12 1/4 and 16/3 and see whether we get 65 1/4!

$\dashrightarrow\tt12 \dfrac{1}{4} \times \dfrac{16}{3}$

$\dashrightarrow \tt \dfrac{49}{4} \times \dfrac{16}{3}$

Cancelling the numbers,

$\dashrightarrow\tt \dfrac{49}{1} \times \dfrac{4}{3}$

$\dashrightarrow\tt \dfrac{196}{3}$

$\dashrightarrow \tt65 \dfrac{1}{4}$

We get 65 1/4 on multiplying 12 1/4 with 16/3.

Hence verified!!

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Know more :-

What are rational numbers?

• The numbers which can be expressed in the form of p/q where p and q are integers and q ≠ 0 are called rational numbers.