Question

product of  [-3/8a³b² ×b³c] [8a³c²/b²×b²]

Answer 1

$(\frac{-3}{8 a^{3}b^{2}}b^3c)( \frac{8 a^{3} c^{2} }{ b^{2} } b^2)$
-3bc.c^2
-3bc^3

Answer 2

-3bc^3=(-3/8a^3b^2.b^3)(8a^3c^2/b^2.b^2)