Question

product of 4 consecutive positive integer is 840 find the numbers

Answer 1

Heyaaa mate

Here is your answer:-

Let the consecutive numbers be x , x+1 , x+2 ,x+3

ATQ,

Their sum is 840

Now,

$x + x +1 + x + 2 + x + 3 = 840$

$4x + 6 = 840$

$4x = 840 - 6$

$4x = 834$

$x = \frac{834}{4}$

$x = 208.5$

Now,

x = 208.5

x + 1 = 208.5 + 1 = 209.5

x + 2 = 208.5 + 2 = 210.5

x + 3 = 208.5 + 3 = 211.5

Check,

208.5 + 209.5 + 210.5 + 211.5

= 840

Hence,

Correct✔️✔️

Hope it helps you

Thanks

Answer 2

Hey Mate ___!!!

The product of four consecutive positive integers is 840. Find the numbers.

Answers

Let x be the average of the four consecutive positive integers. x is a fraction that has 0.50 as its decimal part.

Then the numbers are:    x-1.5,  x-0.5,  x+0.5, x+1.5

Product:   (x-1.5)(x+1.5) (x-0.5)(x+0.5) = 840
                 (x² - 2.25) (x² - 0.25) = 840
                 x⁴ - 2.50 x² -  839.4375
                 x² =  [2.50 +- √(2.50² +
4*839.4375) ] /2
                     =  [ 2.50 +- 58] /2
                     =  30.25
                 x = 5.5

So the numbers are = 4, 5, 6, 7
==============

It can be done by factorization also:

840 = 2 ×2 × 10 ×21 = 2×2×2×3×5×7
                                = ×4×5×6×8

             by rearranging the factors.

Thanks _!!