Question

Product of::a. (x+4) (x+12) b. (x+10) (x-5) c. (x-2) (x-3)

Answer 1

Step-by-step explanation:

a) x^2+16x+48

b). x^2-5x-50

c). x^2-5x+6

Answer 2

$\Huge \underline {\red {\bf{Answer}}}$

$\Large \sf{ Using \: identity:}$

$\underline{\boxed {{ \sf{:\mapsto{(x + a)(x + b) = {x}^{2} + (a + b)x + ab}}}}}$

$\Large \sf{Then,}$

$\sf{a)(x+4)(x+12)={(x)}^{2} + (4+ 12)x + 4 \times 12} \\ \implies \boxed{ \bf{ {x}^{2} + 16x + 48}}$

$\sf{b)(x+10)(x-5) = (x + 10) \{x + ( - 5) \}} \\ \sf \implies{ {x}^{2} + \{10 + ( - 5) \} x+ 10 \times ( - 5)} \\ \implies{\boxed{ \bf{ {x}^{2} + 5x - 50}}}$

$\sf{c)(x-2)(x-3) = \{x + ( - 2) \} \{x + ( - 3) \}} \\ \sf \implies{ {x}^{2} + \{ ( - 2) + ( - 3)\}x + ( - 2)( - 3)} \\ \implies \boxed{ \bf{ {x }^{2} - 5x + 6}}$