Math, asked by Liquidhawk561, 7 months ago

Product of::a. (x+4) (x+12) b. (x+10) (x-5) c. (x-2) (x-3)

Answers

Answered by Anonymous
2

Step-by-step explanation:

a) x^2+16x+48

b). x^2-5x-50

c). x^2-5x+6

Answered by shaktisrivastava1234
3

 \Huge \underline {\red {\bf{Answer}}}

  \Large \sf{ Using \:  identity:}

 \underline{\boxed {{ \sf{:\mapsto{(x + a)(x + b) =  {x}^{2}  + (a + b)x + ab}}}}}

 \Large \sf{Then,}

 \sf{a)(x+4)(x+12)={(x)}^{2} + (4+ 12)x + 4 \times 12} \\   \implies \boxed{ \bf{ {x}^{2} + 16x + 48}}

 \sf{b)(x+10)(x-5) = (x + 10) \{x + ( - 5) \}} \\  \sf \implies{ {x}^{2} +  \{10 + ( - 5) \} x+ 10 \times ( - 5)} \\  \implies{\boxed{ \bf{ {x}^{2} + 5x - 50}}}

 \sf{c)(x-2)(x-3) =  \{x + ( - 2) \} \{x + ( - 3) \}} \\  \sf \implies{ {x}^{2} +  \{ ( - 2) + ( - 3)\}x + ( - 2)( - 3)} \\  \implies \boxed{ \bf{ {x }^{2}  - 5x + 6}}

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