product of first 60 consecutive positive integers
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897 is the first 6o consecutive positive integers
ashwini46376pbs8tq:
sorry, but the answer is wrong. The correct answer is 601. I also want to know the procedure for the same.
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(Ap:1,2,3,...............,60.
Sum of first 60 consecutive integers=n(n+1)/2.
=60(60+1)/2
=60×61/2
=3660/2
1830
Sum of first 60 consecutive integers=n(n+1)/2.
=60(60+1)/2
=60×61/2
=3660/2
1830
Mam, I asked to find the product not sum. please review the question.
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