Question

Product of first ten natural numbers = 2^a×3^b×5^c×7^d then find the value of a+b+c+d
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Answer 1

We have 1*2*3*4*5*6*7*8*9*10

=2*3*2*2*5*2*3*7*2*2*2*3*3*2*5

=2^8*3^5*5^2*7

therefore,

a=8

b=4

c=2

d=1

therefore, a+b+c+d=8+4+2+1

                               =15

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