Math, asked by ashwinishruthi2015, 10 months ago

Product of first ten
natural
numbers =
2a x 3b x 5c x7d
find the value of
a+b+c+d.​

Answers

Answered by vyomamin631
2

Answer:

x2x3x4x5x6x7x8x9x10 = 2x3x2x2x5x2x3x7x2x2x2x3x3x2x5

                                         = 28 x 34 x 52 x 71  = 2a x 3b x 5c x 7d

a = 8, b =4, c =2 , d=1

a + b +c +d = 8 + 4 + 2 + 1 = 15 

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