product of four consecutive natural numbers is 840. find the numbers. (using quadratic equations in one variable)
Answers
Answered by
3
let the consecutive natural terms be x,x+1,x+2,x+3 (x>0)
given
x(x+1)(x+2)(x+3)=840
(x^2+x)(x^2+5x+6)=840
given
x(x+1)(x+2)(x+3)=840
(x^2+x)(x^2+5x+6)=840
Akash7k:
i have done that much do the next step
ok
I will try later now I am busy
ok
I will complete it answer today or tomorrow
Similar questions