Question

Product of rational number (-4)/7 and its additive inverse is *

Answer 1

Answer:-16/49

Step-by-step explanation: the additive inverse of -4/7seventh is 4/7.

The product of -4/7 and 4/7 is -16/49.

-4/7 * 4/7 = -16/49

Plz don't forget to rate me five staes and mark me the brainliest.

Answer 2

Answer:

Here we should find the additive invese of $-\frac{4}{7}$ and we can product that both number. Answer: $(-\frac{16}{49})$

Step-by-step explanation:

To solve the given question, First we should know about the additive inverse.

Additive Inverse:

• Additive inverse is a number which is added to the original number it should give the result as zero(0).
• For that we should change the sign of the original number is the additive inverse.
• Example: Consider as 4 is a number. Additive inverse of that number is -4.

Step 1: Rational number in the given question is, $-\frac{4}{7}$

Step 2: To find the Additive inverse of the given rational number is, change the sign or symbol of $-\frac{4}{7}$. That is,

          Additive inverse of $-\frac{4}{7}$ $=\frac{4}{7}$

• Minus(-) sign changed into Addition(+) symbol.

Step 3: Product of rational number  $-\frac{4}{7}$ and its additive inverse ($\frac{4}{7}$).

                            $=(-\frac{4}{7})\times\frac{4}{7}$

• We can't cancel 4 and 7 .So that, Multiply the numerator values(-4 and 4) and the denominator values(7 and 7).
• And multiply the sign symbol ⇒ $(-) \times (+) = (-)$

             $(-\frac{4}{7})\times\frac{4}{7} = -\frac{16}{49}$      

Answer: $(-\frac{16}{49})$