Product of roots of the equation x-√3x-6=2 is
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Case II: When x<0, then equation is. −x2−5x−6=0. ⇒x2+5x+6=0. ⇒(x+2)(x+3)=0. ⇒x=−2or −3. So, the required roots are −3,−2,−1,6. Therefore, product of the roots =(−3)(−2)(−1)(6)=−36. Answer v
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