Question

Product of the zeros of -2x²+kx+6

Answer 1

let

zeros of given eq^n. is a and b.

so product of zeros is

a×b= constant part/coefficient of x^2.

a×b=6/-2

=-3.

please feedback me this ans

Answer 2

Answer:

Step-by-step explanation:

Let roots are α and β

αβ=32

=> α=32β.....(1)

Then

Product of roots = ca

=> αβ=6

=> 32ββ=6

=> β2=4

=> β=±2

Putting in (1) we get

α=±3

Now sum of roots = −ba

=> 3 + 2 = k or -3 + (-2) = k

=> k = 5 or k = -5