Question

product of the zeros of the polynomial x^2+10x+24 will be

Answer 1

Hello, Buddy!!

||Required Solution||

${x}^{2} + 10x + 24 = 0 \\ {x}^{2} + 6x + 4x + 24 = 0 \\ x(x + 6) + 4(x + 6) = 0 \\ (x + 6)(x + 4) = 0 \\ x = - 6 \: (or) \: - 4$

Product of Roots

→ (-6)(-4)

→ 24

• Product of Zero = αβ → c/a

Where, α & β are roots of QE. The Quadratic Equation is ax²+bx+c = 0

Here, a = 1, b = 10 & c = 24

→ 24/1

→ 24

• Product of Roots ☞ 24

@MrMonarque♡

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