Question

product of three numbers is 384 difference 4 find 3 numbers​

Answer 1

Step-by-step explanation:

a-3d, a-d, a+d, a+3d are 4 terms in an AP

(a-3d) + (a-d) + (a+d) + (a+3d) = 4

a - 3d + a - d + a - d + a + 3d = 4

4a = 4

a=1

(a-3d)(a-d)(a+3d)(a+d) = 385

(a^2 - 3d^2)(a^2 - d^2 ) = 385

Using a =1

( 1 - 3d^2) ( 1 - d^2 ) = 385

1 - d^2 - 3d^2 + 3d^4 = 385

3d^4 - 4d^2 - 384 = 0

3d^4 - 3d^2- d^2- 384

Factorise 9d⁴-10d²-385

and we get d=8/3