Question

Product of three positive integers A, B and
are 480. C equals to 4 and X is average of
and B. Find the minimum possible value of
10:09 AM
X.
AM​

Answer 1

Answer:

Correct option is

B

2

2/3

We know, from AM≥GM, for positive quantities, that

3

(a+b+c)

≥

3

abc

3

(a+c)+b

≥

3

abc

But 2b=(a+c).

This implies

3

3b

≥(4)

1/3

b≥(2)

2/3