product of two consecutive odd numbers is 143, then find the numbers
Answers
Answered by
39
Let x be the first odd number.
Then the second odd number is x+2 since there is a common difference of 2 between all odd numbers.
Then x(x+2) = 143
x^2 + 2x = 143
x^2 + 2x -143 = 0
What multiplies to -143 and adds to 2?
It may take a while to think of the answer, but let's just think about this for a second.
We need two numbers that add up to 2.
Start with -10 and 12 which is -120... too low
-11 and 13? -143... perfect.
So we get (x-11) and (x+13) Which gives us x =11 and x=-13. It's not likely that our answer is negative, so let's stick with x =11.
Then our second odd number is 11+2 = 13
So our numbers are 11 and 13.
Then the second odd number is x+2 since there is a common difference of 2 between all odd numbers.
Then x(x+2) = 143
x^2 + 2x = 143
x^2 + 2x -143 = 0
What multiplies to -143 and adds to 2?
It may take a while to think of the answer, but let's just think about this for a second.
We need two numbers that add up to 2.
Start with -10 and 12 which is -120... too low
-11 and 13? -143... perfect.
So we get (x-11) and (x+13) Which gives us x =11 and x=-13. It's not likely that our answer is negative, so let's stick with x =11.
Then our second odd number is 11+2 = 13
So our numbers are 11 and 13.
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Answered by
29
Answer:
Explanation:
First number: x
Second number:x+2
Given,
Product of two consecutive odd number is equal to 143
X(x+2)=143
X^2+2x-143=0
x^2+13x-11x-143=0. By splitting the middle terms
X(x+13)-11(x+13)=0
(x+13) (x-11)=0
X=-13,11
Hence, two consecutive odd number are -13 and 11
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