Question

product of two consecutive odd numbers is 6723 find the square root of smallest number

Answer 1

Consecutive numbers are numbers that follow each other in order.

Examples. 1, 2, 3, 4, 5……

Let the first odd number be x.

Then, the other odd number would be x + 2.(x+2 because if will we take (x+3) it would become a even number)

∴ x(x+2) = 6723

= x2 + 2x = 6723

= x2 + 2x = 6723

= x2 + 2x - 6723 = 0

= x2 + 83 - 81 x - 6723 = 0

= x(x+83) - 81 (x + 83) = 0

= (x + 83) (x - 81) = 0

= (x + 83) (x - 81) = 0

= x - 81 = 0

∴ x = 81

Hence, greater number = x + 2 = 81 + 2 = 83

Answer 2

❤❤here is your answer ✌ ✌

Let the first odd number be x, the other wold be (x+2)

So, x(x+2)=6723

Short cut is try factorizing 6723 as

6723=9*747=9*9*83=81*83

x (x+2)=81*83

x=81