Question

product of two consequetive numbers is 72 find the numbers

Answer 1

let the one no be x
the other consecutive no will be x+1

A/Q

x×(x+1)= 72

X^2+X=72

X^2-72+X=0

X^2+9X-8X-72=0

X(X+9)-8(X+9)=0

(X-8)+(X+9)=0

EITHER. OR

X=8. X= -9

SINCE X=-9 is negative. We will take X=8

the other consecutive no= x+1
8+1=9

two consecutive no will be 8and 9

Answer 2

Let first no. = x
and second no. = x+1
X(x+1) =72
X^2+x-72 =0.
X^2+(9-8)x-72=0
X^2+9x-8x - 72=0
X=8
X+1=8+1= 9