Question

product of two natural numbers is 17.find the sum reciprocals.​

Answer 1

QUESTION:

product of two natural numbers is 17.find the sum reciprocals

SOLUTION:

Let M and N be two natural numbers (positive integers), such that M×N = 17.

Since 17 is prime, one of the two numbers is and the other is 17.

Let M=1 and N=17

Then the sum of reciprocals of their squares is:

$\\ \\ \\ \\ = \frac{1}{ {m}^{2} } + \frac{1}{{n}^{2} } \\ \\ \\ = \frac{1}{ ({1})^{2} } + \frac{1}{ {(17)}^{2} } \\ \\ = \frac{1}{1} + \frac{1}{289} \\ \\ = \frac{290}{289} \: \: \: \: \: \: answer$

Answer 2

Answer:

∴ ∠ABC = 90° [angle in semi circle] ---- (i)

Also, AD is a diameter of the circle with center O .

∴ ∠ABD = 90° [angle in semi circle] ---- (ii)

on adding Eqns, (i) and (ii) we get

⇒ ∠ABC + ∠ABD = 180°

So. CBD is a straight line.

Hence C, B and D are collinear . Hence proved.